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因式分解 (a-1)(a+1)(a+3)(a+5)+16
人气:264 ℃ 时间:2020-05-08 09:19:38
解答
(a-1)(a+1)(a+3)(a+5)+16
=[(a-1)(a+5)][(a+1)(a+3)]+16
=(a^2+4a-5)(a^2+4a+3)+16
=(a^2+4a)^2-2(a^2+4a)-15+16
=(a^2+4a-1)^2
=(a-√5+2)^2(a+√5+2)^2
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