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计算:(m+n)(m-n)[mn-(m+n)²][(m-n)²+mn]
人气:127 ℃ 时间:2020-02-04 10:32:58
解答
:(m+n)(m-n)[mn-(m+n)²][(m-n)²+mn]=(m+n)(m-n)[mn-(m²+2mn+n²)(m²-2mn+n²+mn)=-(m+n)(m²-mn+n²)(m-n)(m²+mn+n²)=-(m³+n³)(m³-n³)=-(m^6-n...
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