-x^2+2kxy-4y^2+xy-5x-1中含有xy项为:2kxy+xy=(2k+1)xy
多项式中不含有xy项
即2k+1=0
k=-1/2
多项式恒等于一个常数的说法正确
(x^3+3x^2y-2xy^2+1)+(-xy^2+x^2y-2x^3+2)+(x^3-4x^2y+3xy^2-8)
=x^3+3x^2y-2xy^2+1-xy^2+x^2y-2x^3+2+x^3-4x^2y+3xy^2-8
=x^3-2x^3+x^3+3x^2y+x^2y-4x^2y-2xy^2+3xy^2-xy^2-8+1+2
=3x^2y+x^2y-4x^2y-2xy^2+3xy^2-xy^2-5
=-2xy^2+3xy^2-xy^2-5
=-5
经化简多项式的值与x,y无关