设函数z=sin(x^2y^2)+3x-5y^2+1,求dz_数学解答

设函数z=sin(x^2y^2)+3x-5y^2+1,求dz

人气：330 ℃　时间：2020-06-04 16:46:54

解答

z=sin(x²y²)+3x-5y²+1所以δz/δx=cos(x²y²)*2xy²+3δz/δy=cos(x²y²)*2x²y-10y所以dz=(δz/δx)dx+(δz/δy)dy=[cos(x²y²)*2xy²+3]dx+[cos(x²y&...