解x=1/(2-√3)=(2+√3)/(2-√3)(2+√3)=2+√3∴x-2=√3两边平方得：(x-2)²=(√3)²=3∴x²-4x+2=(x²-4x+4)-2=(x-2)²-2=3-2=1[(a-1)+2/(a+1)]÷(a²+1)——这个吗?=[(a-1)(a+1)/(a+1)+2/(...