> 数学 >
函数f(x)=(x-6)/(x^2-4x-12)的连续区间为_____,间断点是______?
人气:429 ℃ 时间:2020-02-04 07:34:04
解答
f(x)=(x-6)/(x^2-4x-12)=(x-6)/(x-6)(x+2)
函数f(x)=(x-6)/(x^2-4x-12)的连续区间为(-无穷,-2)∪(-2,+无穷)间断点是x=-2
推荐
猜你喜欢
© 2026 79432.Com All Rights Reserved.
电脑版|手机版