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化简f(x)=2又根号3sin(wx/2)cos(wx/2)-2sin^2wx/2
人气:161 ℃ 时间:2020-05-12 05:46:51
解答
f(x)=2又根号3sin(wx/2)cos(wx/2)-2sin^2wx/2
=根号3sinwx+(1-2sin^2wx/2)-1
=根号3sinwx+coswx-1
=2(sinwx*cosπ/6+coswx*sinπ/6)-1
=2sin(wx+π/6)-1
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