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这些初二计算题怎么写?步骤要出来,
x²-(x-y)²
(x+2y)²-(2x-y)²
(x+y+z)²-(x-y-z)²
(a-b) ^4-(b-a)²
人气:228 ℃ 时间:2020-10-02 01:17:41
解答
x²-(x-y)²=x²-x²+2xy-y²=2xy-y²(x+2y)²-(2x-y)²=x²+4xy+4y²-4x²+4xy-y²=3y²+8xy-3x²(x+y+z)²-(x-y-z)²=(x+y+z-x+y+z)(...能把他修改改成分解因式的形式么,我在给你加10~20分··可以。x²-(x-y)²=(x-x+y)(x+x-y)=y*(2x-y)=2xy-y²(x+2y)²-(2x-y)²=(x+2y-2x+y)(x+2y+2x-y)=(3y-x)(3x-y)=9xy-3x²-3y²-xy=8xy-3x²-3y²(x+y+z)²-(x-y-z)²=(x+y+z-x+y+z)(x+y+z+x-y-z)=(2y+2z)*2x=4xy+4xz(a-b) ^4-(b-a)²=(a-b)²[(a-b)²-1)=(a²-2ab+b²)(a²-2ab+b²-1)=a^4-2a³b+a²b²-a²-2a³b+4a²b²-2ab³+2ab+a²b²-2ab³+b^4-b²=a^4-4a³b+6a²b²-a²-4ab³-b²+^4
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