计算行列式：a 1 0 0 -1 b 1 0 0 -1 c 1 0 0 -1 da 1 0 0 ；-1 b 1 0；0 -1 c _数学解答

计算行列式：a 1 0 0 -1 b 1 0 0 -1 c 1 0 0 -1 d
a 1 0 0 ；
-1 b 1 0；
0 -1 c 1；
0 0 -1 d；

人气：307 ℃　时间：2019-10-17 06:48:34

解答

a,1,0,0-1,b,1,00,-1,c,10,0,-1,dr2+(1/a)r1:a,1,0,00,(ba+1)/a,1,00,-1,c,10,0,-1,dr3+[a/(ab+1)]r2:a,1,0,00,(ba+1)/a,1,00,0,(cba+c+a)/(ba+1),10,0,-1,dr4+[(ba+1)/(cba+c+a)]r3:a,1,0,00,(ba+1)/a,1,00,0,(cba+...