1-1/6+1/42+1/56+1/72=1/4+1/28+1/70+1/130+1/208=6*7/12-9/20*6+11/3_数学解答

1-1/6+1/42+1/56+1/72=
1/4+1/28+1/70+1/130+1/208=
6*7/12-9/20*6+11/30*6=
9.6+99.6+999.6+9999.6=

人气：347 ℃　时间：2020-06-02 17:03:59

解答

1-1/6*(1-1/7)+1/8*(1/7+1/9)=1-1/7+2/63=56/63;
1/4+1/(4*7)+1/(7*10)+1/(10*13)+1/(13*16)=1/4+1/7(1/4+1/10)+1/13(1/10+1/16)=1/4+1/20+1/80=5/16
1/12(42-9/10+11/15)
(10-0.4)+(100-0.4)+(1000-0.4)+(10000-0.4)=11110-1.6=11108.4