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(x+3)/(x+1)指数2x+1极限(x趋向无穷大)
人气:266 ℃ 时间:2020-01-09 04:43:18
解答
[(x+3)/(x+1)]^(2x+1)=[1+2/(x+1)]^[(x+1)/2*4-1]
={[1+2/(x+1)]^[(x+1)/2]}^4/(1+2/(x+1))=e^4/1=e^4
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