已知一个半径为2,圆心角为45度的一个扇形,求弧长和面积
人气:236 ℃ 时间:2019-10-18 02:56:58
解答
弧长=2πrθ/360
=2×3.14×2×45÷360
=1.57(厘米)
面积=πr²θ/360
=3.14×2²×45÷360
=1.57(平方厘米)
答:弧长1.57厘米,面积1.57平方厘米
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