把多项式(xy-1)²+(x+y-2)(x+y-2xy)分解因式
人气:292 ℃ 时间:2019-09-19 03:40:41
解答
(xy-1)²+(x+y-2)(x+y-2xy)
=x²y²-2xy+1+(x+y)²-2xy(x+y)-2(x+y)+4xy
=x²y²+2xy+1+(x+y)²-2xy(x+y)-2(x+y)
=(xy+1)²-2(xy+1)(x+y)+(x+y)²
=(xy+1-x-y)²
=[x(y-1)-(y-1)]²
=(x-1)²(y-1)²
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