计算:[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y
人气：307 ℃ 时间：2020-01-01 10:07:26
解答
[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y
=(x^3y^2-x^2y-x^2y+x^3y^2)/3x^2y
=(2x^3y^2-2x^2y)/3x^2y
=2/3xy-2/3
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