设x y是有理数,且x、y满足等式x^2+2y+√2y=17-4√2,求(x的绝对值+y)^20102的值.
人气:389 ℃ 时间:2019-08-17 23:49:49
解答
“√”这是什么符号?如果是根号的话,下面讲解解题步骤.x是有理数,则x^2依然是有理数;y是有理数,则2y依然是有理数;y*2^0.5 =-4*2^0.5,.所以y=-4,则│x│=5.则│x│+y=1,所以(│x│+y)^20102=1.
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