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一道平方差数学题
(1/2+1)(1/2^2+1)(1/2^4+1)(1/2^8+1)(1/2^16+1)+1/2^31
人气:370 ℃ 时间:2020-03-30 18:31:04
解答
(1/2+1)(1/2^2+1)(1/2^4+1)(1/2^8+1)(1/2^16+1)+1/2^31
=2*(1-1/2)(1/2+1)(1/2^2+1)(1/2^4+1)(1/2^8+1)(1/2^16+1)+1/2^31
=2*(1-1/2^32)+1/2^31
=2-1/2^31+1/2^31
=2神马意思
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