a+b+c=1
2a+2b+2c=2
2=(a+b)+(b+c)+(c+a)
≥2√ab+2√bc+2√ca
(√a+√b+√c)²
=a+b+c+2√ab+2√bc+2√ca
≤1+2=3
开方得
√a+√b+√c≤√3
如果您认可我的回答,请点击“采纳为满意答案”,谢谢!