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数学
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求极限lim(x^2-6x+8)/(x^2+x-6)
人气:414 ℃ 时间:2020-05-02 01:40:56
解答
说明:此题不完整.
应该是“求极限lim(x->2)(x^2-6x+8)/(x^2+x-6)”.
原式=lim(x->2){[(x-2)(x-4)]/[(x-2)(x+3)]}
=lim(x->2)[(x-4)/(x+3)]
=(2-4)/(2+3)
=-2/5
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