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[m(mn^3)^2-2(mn^2)^3-1]·(m^2n)^3
人气:155 ℃ 时间:2020-03-22 05:36:59
解答
[m(mn^3)^2-2(mn^2)^3-1]·(m^2n)^3
=[m(m^2n^6)-2(m^3n^6)-1]·(m^6n^3)
=[m^3n^6-2m^3n^6-1]·(m^6n^3)
=[-m^3n^6-1]·(m^6n^3)
=-m^9n^9-m^6n^3
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