>
其他
>
(1/2)*cosα-[(√3/2)*sinα]=1,求α的值
人气:170 ℃ 时间:2020-07-29 18:01:40
解答
(1/2)*cosα-[(√3/2)*sinα]=sin30*cosα-cos30*sinα=sin(30-α)=1
30-α=360k+90
α= -360k-60=360k'+300
以上都是角度 有需要自己整弧度吧 α如果有取值范围也自己整吧
推荐
若sin(π/6-α)=1/3,则cos(2π/3+2α)的值?请针对每一步做说明,清楚一点.
若cos(π+α)=-1/2,3/2π
若sinβ=1/3,cos(α+β)=1,则sin(2α+β)的值
已知sin(α-π/4)=1/3,则cos(π/4+α)的值为——
已知sin(π/2+α)=1/3,则cos(π+2α)的值是?
the pen didn't work.转换成there was --- ----with the pen.
解不等式一题~
在:42.44.44.46.48.48.48.50.51.51.56
猜你喜欢
印第安酋长谁又向我们道出了“这片土地是神圣的”心声.
已知2a-1的平方根是正负3,3a+2b-1的立方根是3,求a+b的平方根
氢气在氯气中燃烧生成氯化氢气体,燃烧100克氢气需要氯气多少克?生成氯化氢气体多少克?
Have you decided the time______ you will spend on holidays.
哈尔滨6月份和12月份分别几点天黑几点天亮?也就是说一年中白天最长和最短的大概是几点到几点?
还有一句:How i wish that your here with me to cheer me up in my work and help me do my work
yes of course we does
求镍基合金的焊接工艺
© 2025 79432.Com All Rights Reserved.
电脑版
|
手机版