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初一数学的十字相乘法
1.x的平方+3ax-10a的平方-x+2a
2.(x的平方-7x+6)(x的平方-x-6)+56
人气:260 ℃ 时间:2020-05-08 14:15:08
解答
1.x的平方+3ax-10a的平方-x+2a
=x2+(3a-1)x-10a2+2a
=x2+(3a-1)x-2a(5a+1)
=(x+5a-1)(x-2a)
2.(x的平方-7x+6)(x的平方-x-6)+56
=(x-1)(x-6)(x-3)(x+2)+56
=(x-1)(x-3)(x-6)(x+2)+56
=(x2-4x+3)(x2-4x-12)+56
设x2-4x+3=A.得
A*(A-15)+56
=A2-15A+56
=(A-7)(A-8)
=(x2-4x-4)(x2-4x-5)
=(x2-4x-4)(X-5)(X+1)
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