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数学
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已知a,b互为相反数,c,d互为倒数,x的绝对值等于2,试求:x²-(a+b+cd)x+(a+b)2010次方+(-cd)2009
人气:119 ℃ 时间:2019-08-17 16:47:57
解答
a,b互为相反数,a+b=0
c,d互为倒数,cd=1
x的绝对值等于2,x=±2
x^2-(a+b+cd)x+(a+b)2010次方+(-cd)2009
=2^2-(0+1)x+0^2010+(-1)^2009
=4-x+0-1
=3-x
=3±2
=1或5
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