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计算:(1²-2)/(1+2)+(2²—3²)/(2+3)+……+(99²—100²)/(99+100)
人气:291 ℃ 时间:2020-01-26 09:56:38
解答
(1²-2²)/(1+2)+(2²—3²)/(2+3)+……+(99²—100²)/(99+100)= (1+2)(1-2)/(1+2)+(2+3)(2-3)/(2+3)+...+(99+1000)(99-100)/(99+100)=1-2+2-3+...+99-100=1-100=-99...
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