(3x^2y-2xy^2)-(xy^2-2x^2y)-3(x^2y^2+x^2y)+3(x^2y^2=xy^2) 其中x=-1 y_数学解答

(3x^2y-2xy^2)-(xy^2-2x^2y)-3(x^2y^2+x^2y)+3(x^2y^2=xy^2) 其中x=-1 y=2
(3x^2y-2xy^2)-(xy^2-2x^2y)-3(x^2y^2+x^2y)+3(x^2y^2+xy^2) 其中x=-1 y=2

人气：237 ℃　时间：2020-05-08 20:48:11

解答

(3x^2y-2xy^2)-(xy^2-2x^2y)-3(x^2y^2+x^2y)+3(x^2y^2+xy^2)
=3x^2y-2xy^2-xy^2+2x^2y-3x^2y^2-3x^2y+3x^2y^2+3xy^2
=2x^2y
=2(-1)^2×2
=4