已知非零函数a.b满足：(asin(π/5)+bcos(π/5))/(acos(π/5)-bsin(π/5))=tan8π/5,求b/a的值
人气：250 ℃ 时间：2020-06-05 13:31:14
解答
(asin(π/5)+bcos(π/5))/(acos(π/5)-bsin(π/5))=tan8π/5=tan3π/5=sin3π/5/cos3π/5asinπ/5cos3π/5+bcosπ/5cos3π/5=acosπ/5sin3π/5-bsinπ/5sin3π/5bcosπ/5cos3π/5+bsinπ/5sin3π/5=acosπ/5sin3π/5...
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