[x＋√(xy)]／[√(xy)＋y]＋[√(xy)－y]/[x－√(xy)]
=[x＋√(xy)]*[√(xy)-y]/(xy-y²)＋[√(xy)－y]*[x+√(xy)]/(x²-xy)
=[x√(xy)-y√(xy)]/[y(x-y)]+[x√(xy)-y√(xy)]/[x(x-y)]
=√(xy)/y+√(xy)/x
=√(xy)(x+y)/xy
=√[(√3+1)(√3-1)](√3+1+√3-1)/[(√3+1)(√3-1)]
=√2*2√3/2=√6
对吗.