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数学
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如图,已知AB=AC,AD=AE.求证:BD=CE.
人气:306 ℃ 时间:2019-10-21 22:08:40
解答
证明:作AF⊥BC于F,
∵AB=AC(已知),
∴BF=CF(三线合一),
又∵AD=AE(已知),
∴DF=EF(三线合一),
∴BF-DF=CF-EF,即BD=CE(等式的性质).
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