若lim(n→∞) [(3n^2+2/n+1)-an+b]=5,则a/b=多少?
人气:209 ℃ 时间:2020-05-19 16:32:54
解答
lim(n→∞) [(3n^2+2/n+1)-an+b] = 3n-an+b
a=3 b=5 a/b=3/5
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