已知a的平方-a-1=0则a的三次方-2a+2010=
人气:451 ℃ 时间:2019-11-01 02:18:45
解答
a³-2a+2010
=a(a²-a-1)+a²-a+2010
=a(a²-a-1)+(a²-a-1)+2011
=0+0+2011
=2011
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