令x+ (x分之1)=y,那么原方程可化为：y²- 2y-8=0(y-4)(y+2)=0解得：y=4或y=-2当y=4时,x+ (x分之1)=4,即x²-4x+1=0,(x-2)²=3,解得：x=2+根号3或x=2-根号3；当y=-2时,x+ (x分之1)=-2,即x²+2x+1=0,(x...