这是一道常见题,证法有很多cotA+cotB+cotC=cotA+(sinBcosC+cosBsinC)/(sinBsinC)=cotA+2sin(B+C)/[-cos(B+C)+cos(B-C)]=cotA+2sinA/[cosA+cos(B-C)]因为cos(B-C)≤1所以sinA/[cosA+cos(B-C)]≥sinA/(cosA+1)所以cotA...