(1) y = (2x^3-3x^2+3)(√x+1/x) = 2x^(7/2)-3x^(3/2)+3x^(1/2)+2x^2-3x+3/x,
　dy = [7x^(5/2)-(9/2)x^(1/2)+(3/2)x^(-1/2)+4x-3-3/x^2]dx.
　　(2) y = (cosx^2)^3,
　dy = 3[(cosx^2)^2](-sinx^2)(2x)dx.