1、设r1和r2分别相切两圆的半径,同时也是关于x的方程x²+px+2=0的两个实根.若这两个圆的圆心距为4,求r1和r2(r1>r2)
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人气:482 ℃ 时间:2020-04-14 15:55:07
解答
依题意可知,r1+r2=4;
又有r1、r2为一元二次方程两实根条件,则r1*r2=2;
以上两方程式联立,加约束条件r1>r2,解算可得:
r1=2+根2,r2=2-根2
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