计算:y^2-x^2/4y^2-x^2-4y^2+4y^2-3xy/(x+2y)(x-2y)
x-1/x^2-3x+2-x+1/x^2+3x+2-x^2/x^2-4
人气:430 ℃ 时间:2019-11-19 11:07:26
解答
(y^2-x^2)/(4y^2-x^2)-(4y^2+4y^2-3xy)/(x+2y)(x-2y) 请检查你的题目,有点问题=(x²-y²)/(x²-4y²)-(4y²+4y²-3xy)/(x+2y)(x-2y)=(x²-y²-4y²-4y²+3xy)/(x+2y)(x-2y)...
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