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数学
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((xy+2)(xy-2)-2x^2y^2+4)除以xy,其中x=10,y=-1/5
((xy+2)(xy-2)-2x^2 y^2+4)化简求值
人气:103 ℃ 时间:2019-10-23 02:57:47
解答
你好,love厨子
[(xy+2)(xy-2)-2x²y²+4]÷(xy)
=[x²y²-4-2x²y²+4]÷(xy)
=(-x²y²)÷(xy)
=-xy
∴当x=10,y=-1/5时,
原式=-[10×(-1/5)]=2
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