(3x+4/x的平方-1-2/x-1)÷x+2/x的平方-2x+1,=[（3x+4-2(x+1))/(x^2-1)] *(x^2-2x+1)/(x+2)=[（3x+4-2x-2)/(x-1)(x+1)] * (x-1)^2/(x+2)=[（x+2)/(x-1)(x+1)] * (x-1)^2/(x+2)=(x-1)/(x+1)其中x是方程8x-5=3x的解则有...