求y=根号下(x-1)(x-2)平方|(x-3)(x-4)平方的导数,急_数学解答

求y=根号下(x-1)(x-2)平方|(x-3)(x-4)平方的导数,急

人气：422 ℃　时间：2019-10-24 04:43:36

解答

=[(x-1)^0.5/(x-3)]*[(x-2)^2/(x-4)^2]
=[(x-1)^0.5/(x-3)]'*[(x-2)^2/(x-4)^2]+[(x-1)^0.5/(x-3)]*[(x-2)^2/(x-4)^2]'
=(2-x)*(5x+1)/[(x-1)^0.5*(x-3)^2*(x-4)^2]