设向量a,b满足a+2b=(2,-4),3a-b=(-8,16),求a·b
人气:470 ℃ 时间:2020-01-28 19:34:26
解答
a+2b=(2,-4),①
3a-b=(-8,16)②
①+2×②,得
7a=(2-8×2,-4+16×2)=(-14,-28)
a=(-2,-4)
2b=(2,-4)-a=(2,-4)-(-2,-4)=(4,0)
b=(2,0)
所以
a·b=(-2,-4)·(2,0)=-2×2+(-4)×0=-4
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