>
数学
>
(2014•河西区三模)设S
n
为等比数列{a
n
}的前n项和,8a
2
+a
5
=0,则
S
5
S
2
等于( )
A. 11
B. 5
C. -8
D. -11
人气:125 ℃ 时间:2020-05-13 18:47:57
解答
设等比数列{a
n
}的公比为q,(q≠0)
由题意可得8a
2
+a
5
=8a
1
q+a
1
q
4
=0,解得q=-2,
故
S
5
S
2
=
a
1
(1−
q
5
)
1−q
a
1
(1−
q
2
)
1−q
=
1−
q
5
1−
q
2
=
1−
(−2)
5
1−
(−2)
2
=-11
故选D
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