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(1-1/2^2)*(1-1/3^2)*...*(1-1/2009^2)*(1-1/2010^2)=
人气:433 ℃ 时间:2020-04-14 01:17:25
解答
(1-1/2^2)*(1-1/3^2)*...*(1-1/2009^2)*(1-1/2010^2)
=(1/2)*(3/2)*(2/3)*(4/3)*...*(2009/2010)*(2011/2010)
=(1/2)*(2011/2010)
=2011/4020
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