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因式分解(1) y的4次方-y²=6, (2) (y-1)²-6(y+1)=-8
(2)(y+1)²-6(y+1)=-8
人气:151 ℃ 时间:2019-10-19 16:59:22
解答
(1)y的4次方-y²=6y的4次方-y²-6=0(y²-3)(y²+2)=0(y+√3)(y-√3)(y²+2)=0∴y=√3或y=-√3(2)第二题应该是:(y+1)²-6(y+1)=-8(y+1)²-6(y+1)=-8(y+1)²-6(y+1)...
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