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lim[(1/n^2+1)+(2/n^2+1)+(3/n^2+1)+.+(2n/n^2+1)]
提出1/n^2+1后
1+2+3……+2n
怎么写Sn?
人气:185 ℃ 时间:2020-06-09 04:54:36
解答
1+2+3……+2n
=(1+2n)*2n/2
=n*(1+2n)
lim[(1/n^2+1)+(2/n^2+1)+(3/n^2+1)+.+(2n/n^2+1)]lim[(1/n^2+1)+(2/n^2+1)+(3/n^2+1)+.+(2n/n^2+1)]
=limit[(2n^2+n)/(n^2+1)]
=2
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