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化简3cos^2x+2cosxsinx+sin^2x
人气:366 ℃ 时间:2020-05-09 09:40:53
解答
3cos^2x+2cosxsinx+sin^2x
=cos^2x+sin^2x+2cosxsinx +2cos^2x
=1+sin2x+2cos^2x
=1+sin2x+1+cos2x
=2+sin2x+cos2x
=2+√2(√2/2sin2x+√2/2cos2x)
=sin(2x+π/4)+2
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