∵一元二次方程有两个不等的实数根∴ k不等于0且Δ>0[-2(k+1)]^2-4*k*(k-1)>0得：k>-1/3且 k不等于0若1/x1+1/x2=0,则:(x1+x2)/x1x2=0∴(x1+x2)=0根据根与系数的关系：x1+x2=2(k+1)/k=0∴k=-1∵k>-1/3且 k不等于0∴k=...