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已知tanα=2,求sin2α的值
人气:332 ℃ 时间:2020-05-20 22:31:22
解答
sin2α
=2sinacosa
=2sinacosa/(sin^2 a+cos^2 a)
=2tana/(tan^2 a+1)
=2*2/(2^2+1)
=4/5
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