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数学
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2x-5+y/3=x+3y/4+7与10(x-y)-4(1-x)/3-y=0 求方程组的解
回答要完整一点
人气:247 ℃ 时间:2020-01-30 05:11:19
解答
x=1212/31
y=1260/31
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方程组x:y:z=7:10:5①,2x+3y=44
解方程组x/7=y/10 ,2x+3y=44
2x-5+y/3=x+3y/4+7与10(x-y)-4(1-x)/3-y=0 求方程组的解
解方程组:(1){x/2=y/3;30% × x-16% × y=2%} (2){2x+3y/4+2x-3y/3=7;2x+3y/3+2x-3y/2=8
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