3^x+27^y+1=3^x+3^3y+1(27^y=[(3)^3]^y=3^3y根据不等式a+b≥2根号（a+b)那么3^x+27^y+1=3^x+3^3y+1≥2根号[3^x*3^3y]+1=2根号【3^(x+3y)】+1因为x+3y-2=0x+3y=2所以3^x+27^y+1≥2根号【3^(x+3y)】+1=2*3+1=73^x+27^y...