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lim(x→+∞)(π/2-arctanx)/sin1/x,
人气:350 ℃ 时间:2020-04-03 01:31:45
解答
lim(x→+∞)(π/2-arctanx)/sin1/x (0/0型未定式)=lim(x-->+∞)[-1/(1+x²)]/(-1/x²*cos(1/x)] 【罗比大法则】=lim(x-->+∞)x²/(1+x²)*1/cos(1/x)=lim(x-->+∞)1/(1/x²+1)*1/cos(1/x)=1/(0...
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