(高数)设幂级数∑anx^n,当n>1时an-2=n(n-1)an,且a0=4,a1=1;(1)求幂级数∑anx^n的和函数S(x)
设幂级数∑anx^n,当n>1时an-2=n(n-1)an,且a0=4,a1=1;
(1)求幂级数∑anx^n的和函数S(x);
(2)求和函数S(x)的极值