> 数学 >
计算:
(1)x2-(x3y-2x2y2)﹢xy
(2)(1-
1
2
)×(1+
1
2
)×(1+
1
4
)×(1+
1
16

(3)(2x-3y)2-(y+3x)(3x-y)
(4)(2a3b2-4a4b3+6a5b4)÷(-2a3b2
人气:247 ℃ 时间:2020-04-04 07:16:48
解答
(1)原式=x2-x3y+2x2y2+xy;
(2)原式=(1-
1
4
)×(1+
1
4
)×(1+
1
16
)=(1-
1
16
)(1+
1
16
)=1-
1
256
=
255
256

(3)原式=4x2-12xy+9y2-9x2+y2=-5x2-12xy+10y2
(4)原式=-1+2ab-3a2b2
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